8-12sin^2x=4cos^2x

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Solution for 8-12sin^2x=4cos^2x equation:


Simplifying
8 + -12sin2x = 4cos2x

Solving
8 + -12in2sx = 4cos2x

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + -12in2sx = -8 + 4cos2x

Combine like terms: 8 + -8 = 0
0 + -12in2sx = -8 + 4cos2x
-12in2sx = -8 + 4cos2x

Divide each side by '-12n2sx'.
i = 0.6666666667n-2s-1x-1 + -0.3333333333cn-2os

Simplifying
i = 0.6666666667n-2s-1x-1 + -0.3333333333cn-2os

Reorder the terms:
i = -0.3333333333cn-2os + 0.6666666667n-2s-1x-1

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